If NH2F2 is polar how did they arrive at that choice?
Using the electronnegativity values how do I find this answer? Do I start subracting the values left to right or greatest to lowest or what?
(Since Flourine has the highest env)
basically can someone tell me when there is more than 2 elements in a compound how do I use the ENV to determine polarity.

Thank you

Polarity in polyatomic molecules isn't quite as straightforward as it is in diatomic molecules. The first step is to figure out where the atoms are in relationship to each other.

For example Carbon dioxide looks something like:
O-C-O
both of the C-O bonds are polar, but they end up cancellign each other out because they are in opposite directions,

Water, on the other hand, looks something more like this:

(a bit exaggerated)
  O
 / \
H   H

Each O-H bond is polar. This time, however, they don't cancel each other out in the up-down direction.

I'm not sure how to answer your specific question, because I suspect there is an error in it. NH₂F₂ would not be a neutral molecule, which is what you have written it as. In general though, you need to figure out the basic arrangement of atoms, figure out the approximate polarity and direction of each bond, and then see where the polarities do and don't cancel out.