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ameera22
Posted
what in coulombs is required to deposit 0.205 g Ag (s) from a solution of Ag (s) of a solution of Ag+ (aq) ?
 
Posts: 2 | Location: usa | Registered: 03-23-05Reply With QuoteEdit or Delete MessageReport This Post
Peteeo
Diamond Enthusiast

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first you'll need to figure the moles of silver deposited.
0.205g/GMW of Silver = moles of silver.
There's a 1:1 Relationship of equivalents of
silver vs Moles of silver.
Coulombs are related to equivalent's By Faradays
F=96,487 Q..

Equivalents of silver * F/equivelant= coulombs.

Instrumental Methods of Analysis, Willard,Merritt&Dean. pp702-704

Good luck
 
Posts: 226 | Location: Vadnais Heights MN. | Registered: 06-15-02Reply With QuoteEdit or Delete MessageReport This Post
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