Given that Gravity is the curvature of space-time in the presence of mass and energy, as proven by the solar eclipse experiment that showed the bending of a star's light rays as they passed by the sun, I have a couple of questions. First, where or what is space-time curving into? Is it into another dimension, just as the surface of a 2D sphere is curved into a 3rd dimension?.
Secondly, I believe this curvature of light around the sun was measured, so many arc seconds per something or other. If the sun were twice as massive, would the curvature be twice as much? What is the significance of the measured value in terms of the shape of the universe itself?

the equation is:

alpha = (4*G*M)/(c^2*b), where alpha is the deflection angle, G is the gravitaional constant, M is the mass of the object (in this case, the sun), c is trhe speed of light, and b is the closest distance that the light gets to the object.... so yes, twice the mass results in twice the curving. The value tells us nothing about the shape of the universe overall, but tells us exactly how much the universe is bent around the sun (since gravity is really just the bending of the universe).

Thanks, m5K, for the response. If you or someone has time, could you please determine alpha when M=3 solar masses and b= Swartzchild Radius (or is it the Chandlezmer limit) of a black hole..I'm trying to see what the maximum angle might be, can it exceed 2 pi radians???

The Chandrasekhar limit is the most mass that the degenerate core of of a star can have before it undergoes a supernova (1.4 solar masses).

The Schwarzschild radius is the point of no return of a black hole... from which even light cannot escape.

I feel I should point out that a mass of three solar masses is the mass that the core of a star must have to collapse into a black hole, but larger and smaller black holes exist. It will drop out of the equation anyway, since you've stipulated that this is at the Schwazschild radius.

The equation is:
Rs=2GM/(c^2)

substituting this in for b in the earlier equation, we get:
alpha = (4*G*M*c^2)/(2*G*M*c^2) = 4/2 = 2

This result doesn't make sense to me.... after some checking, I found that there is a stipulation (not provided in the page to which I linked ) that the gravitational lensing equation as given is only valid where b>>Rs. I'm not sure what the breakdown is, but I assume it has something to do with the factor of 2 that was only explained as a consequence of relativity.

I'll keep looking, but since even my astrophysics textbook relied on this simplification, I don't think that I will find anything.

Methos..thanks for taking the time to check this out...it is interesting that alpha is the same for a black hole of any mass with it's corresponding radius...I don't know the meaning of the 2 either...2 radians, I presume, 114 degrees or so... this means that light from a distant star directly behind a black hole and eclipsed by it on its passage to earth, would appear 114 degrees shifted, coming from the eastern sky if we were looking north toward the black hole and actual position of the star...doesn't make sense, but as you say it's probably not a correct formula for these small values of b. Intriguing.