Silver Enthusiast

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Good question. Everyone has their own measure of time depending on their speed relative to something else. With the traveler traveling at 1/2 lightspeed, and at constant velocity (no force, no acceleration), relative to the stationary observer, there is absolutely no way he can tell whether he is moving away from the observer, or if the observer is moving away from him. Consequently, while the observer sees the traveler's time passing more slowly than his own, the the traveler sees the observer's time passing more slowly than his own time. Both are correct, all time in non-force motion is relative, they each correctly measure their own value of time. It is only when the traveler meets up again with the observer....and he must change his direction of motion and/or speed to do so, which requires a force and an acceleration...that is, he undergoes force motion...then at this point when they compare watches, the travelers watch shows 72 hours elapsed and the observers shows 84. The traveler ahs travelled into the observers future, and has aged 12 hours less than he would have aged had he not chosen to go on his journey. But time has passed completely normally for both during that trip, there is no way to make the comparison until the return.
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| Posts: 625 | Location: Boston | Registered: 06-13-02 |    |
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