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Kendor Platinum Enthusiast	Posted Can someone help me? This is surely really simple but I just can't remember how to do this. The formula x = a*b/y+z solves for 'x'. I need to change this formula to solve for 'a'. Help!
	Posts: 1934 | Location: 39° -84.5° | Registered: 06-28-02

DorianGreyed Site Administrator	Posted Hide Post Multiply both sides by (y+z) x(y+z) = (y+z) * (a*b/y+z) x(y+z) = {(y+z)/1} * (a*b/y+z) x(y+z) = a*b Now divide both sides by b. x(y+z)/b = (a*b)/b x(y+z)/b = a Visit DorianGreyed's Gifts Visit DorianGreyed's Attic
	Posts: 19566 | Location: Lincoln Place, Granite City, Illinois, USA | Registered: 06-03-02

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Peteeo Diamond Enthusiast 2009 Enthusiast of the Year	Posted Hide Post I'm reading your formula left to right as x=(a*b)/(y+z). solve for a x*(y+z)=a*b (x*(y+z))/b=a Rearrange a=x/b*(y+z)
	Posts: 272 | Location: Vadnais Heights MN. | Registered: 06-15-02

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DorianGreyed Site Administrator	Posted Hide Post Well, I was first, but Peteeo may be right. I suspect I've made a silly error somewhere. (But don't forget that I was first!) Visit DorianGreyed's Gifts Visit DorianGreyed's Attic
	Posts: 19566 | Location: Lincoln Place, Granite City, Illinois, USA | Registered: 06-03-02

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DorianGreyed Site Administrator	Posted Hide Post I think we came to the same answer, just expressed slightly differently. Visit DorianGreyed's Gifts Visit DorianGreyed's Attic
	Posts: 19566 | Location: Lincoln Place, Granite City, Illinois, USA | Registered: 06-03-02

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Kendor Platinum Enthusiast	Posted Hide Post Thanks guys!
	Posts: 1934 | Location: 39° -84.5° | Registered: 06-28-02

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DorianGreyed Site Administrator	Posted Hide Post It is I who should thank both you and Peteeo for giving me a chance to stretch my memory. I'm a firm believer in the "Use it or lose it" theory, but I rarely practice my math skills. Mea culpa. Visit DorianGreyed's Gifts Visit DorianGreyed's Attic
	Posts: 19566 | Location: Lincoln Place, Granite City, Illinois, USA | Registered: 06-03-02

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