throw me another bone will ya?

domain and range one more time

f(x)= 2+ sqrt x+3

domain and range

a thousand times thank you for all your help.

I'm assuming that the whole 'x+3' is under the square root.

The square root is what limits the domain. The number under the square root must be equal to or greater than 0.
x + 3 ≥ 0
x ≥ -3

So, that is the domain: x ≥ -3



The square root is again the important part for the range. A square root can give a range of greater than or equal to zero. In this case, however, we have 2 added to that. This doesn't affect the high end of the range (infinity, because infinity plus two is still infinity) but does change the lower end. 0 + 2 is, of course, 2, so the range is
f(x) ≥ 2